This site makes extensive use of JavaScript.
Please enable JavaScript in your browser.
Live
PTR
10.2.7
PTR
10.2.6
Beta
Serious posts are absent in the presence of an observer
Post Reply
Return to board index
Post by
HighFive
Yep.
For example, in a Cartesian coordinate system the vectors (0, 1) and (1, 0) would form an orthonormal basis.
Post by
Interest
*!@# you guys. Making me wanna play VVVVVV.
I don't see the connection.
I don't see the problem either.
You have to actually play the game to understand =).
Post by
pelf
What is VVVVVV? Is it like WoW?
Post by
HighFive
Yes. It's a Korean mmo with focus on open world pvp.
Post by
pelf
Wow, I was joking. That's actually the name of something?
>_>
Post by
HighFive
I was joking too. It's actually a pretty sweet platformer.
Post by
pelf
Is this like the Eddie Izzard standup bit where he goes back and forth between something being true and not true about 20 times?
Post by
HighFive
Sure, that sounds like fun.
Post by
HighFive
What if the odd ball weighs less or more (you don't know which) than the others?
Here's what I've come up with:
I'll label the balls as 1, 2, ... 7.
1 Weigh 1, 2 v/s 3, 4. If they are equal, the odd ball is 5, 6 or 7:
1.1 Weigh 5 v/s 6. If they are equal, the odd ball is 7 (2 weighings). Otherwise, it's 5 or 6:
1.1.1 Weigh 5 v/s 1. If they are equal, the odd ball is 6, otherwise it's 5 (3 weighings).
1 Otherwise, the odd ball is 1, 2, 3 or 4:
1.2 Weigh 1, 2 v/s 5, 6. If they are equal the odd ball is 3 or 4:
1.2.1 Weigh 3 v/s 1. If they are equal, the odd ball is 4, otherwise it's 3 (3 weighings).
1.2 Otherwise, the odd ball is 1 or 2:
1.2.2 Weigh 1 v/s 3. If they are equal, the odd ball is 2, otherwise it's 1 (3 weighings).
Is this correct?
It can't be done in just 2 weighings, can it?
Is there a number of balls that ensures a neat solution like the one where the odd ball is lighter?
Post by
pelf
Funny thing is that I just made up that question. I don't know if it's hard, easy or indifferent. I was really just trolling. Great effect.
Post by
HighFive
Haha. I had heard it before, though.
Post by
Wikipedia
H5, what about
1,2,3 vs 4,5,6 with 7 on the ground. If it's equal, seven is the odd one.
If one sides sinks, you just put a,b with c on the ground. So 2 weighings
:3
Post by
HighFive
I don't get it. What are a, b and c?
Post by
Wikipedia
Placeholders for either 1,2,3 or 4,5,6.
If a+b+c = d+e+f then g is odd
If
1
is false, with a+b+c weighing more, a = b then c is odd.
If
2
is false, repeat
2
with d+e+f.
Post by
HighFive
Does "If 2 is false" mean "if a = b = c"?
Post by
Wikipedia
Oh, yeah.
Post by
Wikipedia
I just found Haskell.
Post by
HighFive
Nice. Have fun.
Post by
Ketho
I just found Haskell.
like, the programming language?
Post by
Wikipedia
Si!
Post Reply
You are not logged in. Please
log in
to post a reply or
register
if you don't already have an account.